0.23x^2+4x+9=15

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Solution for 0.23x^2+4x+9=15 equation:



0.23x^2+4x+9=15
We move all terms to the left:
0.23x^2+4x+9-(15)=0
We add all the numbers together, and all the variables
0.23x^2+4x-6=0
a = 0.23; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·0.23·(-6)
Δ = 21.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{21.52}}{2*0.23}=\frac{-4-\sqrt{21.52}}{0.46} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{21.52}}{2*0.23}=\frac{-4+\sqrt{21.52}}{0.46} $

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